The coefficient of \(x^2\) is positive, so the graph will be a positive U-shaped curve. To find where the ... crosses the \(y\)-axis at \(y = 9\). Sketching a quadratic using the turning point ...
The coefficient of \(x^2\) is positive, so the graph will be a positive U-shaped curve with a turning point ... crosses the \(y\)-axis at \(y = 9\). Sketching a quadratic using the turning point ...
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