Instead of P moving anticlockwise from (1, 0), if it goes clockwise then \(\theta\) will be negative! No matter where P is on the circle, the \(x\)-coordinate gives the value of \(\cos{\theta}\) ...
Instead of P moving anticlockwise from (1, 0), if it goes clockwise then \(\theta\) will be negative! No matter where P is on the circle, the \(x\)-coordinate gives the value of \(\cos{\theta}\) ...
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